Question

$(\alpha -8).(\alpha -8)$

Answer 1

HERE IS YOUR ANSWER:-

$(\alpha - 8)( \alpha - 8) \\ \\ = > {( \alpha - 8)}^{2} \\ \\ = > { \alpha }^{2} - 2 \times 8 \times \alpha + {8}^{2} ......... \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = > {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} \\ \\ \\ = > { \alpha }^{2} - 16 \alpha + 64$

Hope it helps you//...

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