Question

$\alpha + \beta = 2 \\ \alpha \beta = \frac{1}{2} \\ x {}^{2} - (2 \alpha - 3 \beta + 3 \alpha - 2 \beta )x + (2 \alpha - 3 \beta )(3 \alpha - 2 \beta ) = 0$
​

Answer 1

Answer:

I don't know