Question

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question no. 6 and 7✔✔
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Answer 1

Answer:

Explanation:

6)a.

(1100101)2 = (101)10

(101010)₂ = (1 × 2⁵) + (0 × 2⁴) + (1 × 2³) + (0 × 2²) + (1 × 2¹) + (0 × 2⁰) = (42)₁₀

101+42=143

b.

(10101)2 = (21)10  

(11101)2=(29)10

(101011)2 = (43)10

21+29+43=93

c.

(11010111)2 = (215)10

(10110.1)2 = (22.5)10

215-22.5=192.5

d.

(1010101)2 = (85)10

(1101)2 = (13)10

85-13=72

e.

(11101111)2 = (239)10

(1101)2 = (13)10

239*13=3107

f.

(101011)2=(43)10

(11)2=(3)10

43*3=129

g.

(01101)2=(13)10

(11)2=(3)10

13/3=4.3333....

7)a.9=00001001

b.57=00111001

c.128=10000000

d.3398=110101000110

Answer 2

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