Question

$b ^{2} - 9b + 20 = 0$

Answer 1

Hi Friend !!

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b²-9b +20 = 0

b²- 4b - 5b+20 = 0

b(b-4)-5(b-4) = 0

(b-5)(b-4) = 0

b = 5 and 4

Hope it helps u :-)

Answer 2

HELLO.......FRIEND!!

THE ANSWER IS HERE,

$= > \: {b}^{2} - 9b + 20 = 0$

$= > \: {b}^{2} - 4b - 5b + 20 = 0$

=> b (b-4)-5 (b-4)=0

=> (b-4)(b-5)=0.


:-)Hope it helps u.