Question

x^2-6x+9 divided by x^2-9​

Answer 1

Step-by-step explanation:

(x^2 + 6x + 9) / (x^2 - 9) = ((x + 3) (x+ 3)) / ((x + 3) (x - 3)) = (x + 3) / (x - 3)

Then log ((x + 3) / (x - 3)) = log (x + 3) - log (x - 3)

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Answer 2

Answer:

p(x) = x²-6x+9

g(x) = x²-9

Applying factor theorem

g(x) = x²-9

0 = x²-9

x² = 9

x = √9 = 3

p(x) = x²-6x+9

p(3) = (3)²-6(3)+9

= 9-18+9

= 0

Therefore the required answer for this question is 0.

i.e the remainder is 0.

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