Question

$\bf{\boxed{\huge{\mathlab{\color{red}{HOLA \: MATES}}}}$

Class : 9

Subject : Maths

Chapter : Triangles

$\underline{\texit{\large{QUESTION :}}}$

Please refer to the attached pic

______________________

#Be Brainly

Answer 1

Bonjour ❤️

here's your answer____________________

Given :-

BAC = 90°

AL perpendicular to BC

To prove :-

CAL = ABC

Proof :-

In ∆ ALC and ∆ ALB

angle ALC = angle ALB .........( AL perpendicular BC )

AL = AL .......................................( common )

AC = AB .......................................( opposite sides of equal angles are equal )

So,

∆ ALC (congruent) ∆ ALB .....( R.H.S. )

hence,

CAL = ABC ( c.p.c.t ) PROVED//

>>--------☺️--------<<

hope it will help you ✌️✌️
.
.
❤️ THANKS ❤️

# BE BRAINLY

Answer 2

Hope this helps you.