Question

$\bf\frac{4} {5} \: tan² \: 60° + 3 \: sin² \: 60° = \: ?$
​

Answer 1

$\frac{4}{5} tan {}^{2} (60°) + 3 \: sin {}^{2} (60°)$

$\frac{4 \: tan {}^{2}(60°) }{5} + 3 \: sin {}^{2} (60°)$

$\frac{4( \sqrt{3} ) {}^{2} }{5} + 3 \: sin {}^{2} (60°)$

$\frac{4 \times 3}{5} + 3 \: sin {}^{2} (60°)$

$\frac{12}{5} + 3 (\frac{ \sqrt{3} {}^{2} }{2} )$

$\frac{12}{5} + 3 \times \frac{3}{2 {}^{2} }$

$Answer = \frac{93}{20}$

$\mathfrak\blue{Hope \: you \: have \: satisfied}$

Answer 2

Answer:

tan

2

(60°)+3sin

2

(60°)

\frac{4 \: tan {}^{2}(60°) }{5} + 3 \: sin {}^{2} (60°)

5

4tan

2

(60°)

+3sin

2

(60°)

\frac{4( \sqrt{3} ) {}^{2} }{5} + 3 \: sin {}^{2} (60°)

5

4(

3

)

2

+3sin

2

(60°)

\frac{4 \times 3}{5} + 3 \: sin {}^{2} (60°)

5

4×3

+3sin

2

(60°)

\frac{12}{5} + 3 (\frac{ \sqrt{3} {}^{2} }{2} )

5

12

+3(

2

3

2

)

\frac{12}{5} + 3 \times \frac{3}{2 {}^{2} }

5

12

+3×

2

2

3

Answer = \frac{93}{20}Answer=

20

93

\mathfrak\blue{Hope \: you \: have \: satisfied}