Question

${\bf{\huge{Question}}}$

in class 10th of a school the ratio of the number of boys to that of the girls is 4:3 if there were 20 more boys and 12 less girls then the ratio would have been 2:1 how many students were there in the class


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Answer 1

$\huge\fbox\red{❥answer}$

Refer The Attachment..!

I'm not mod nor star or sincere user...but still I answered :p

hope answer correct ho :) lol

Answer 2

Given:

• In class 10th of a school the ratio of the number of boys to that of the girls is 4:3

• If there were 20 more boys and 12 less girls then the ratio would have been 2:1

To Find:

• how many students were there in the class

Solution:

As we have said that the ratio of the boys and girls is 4 : 3. So, let the number of girls be 4x and boys be 3x

${\underline{\bf{\bigstar{According \; to \; the \; question : }}}}$

• if there were 20 more boys and 12 less girls then the ratio would have been 2:1

~ Now let's frame an equation according to the statement given above to find the number of boys and girls,

$\longrightarrow \tt \dfrac{No.of\; boys + 20}{No.of\; girls-12} = \dfrac{2}{1}$

• Now as we have assumed that boys = 4x and girls = 3x

$\longrightarrow \tt \dfrac{4x+20}{3x - 12} = \dfrac{2}{1}$

• Cross multiplying we get,

$\longrightarrow \tt 1(4x + 20) = 2(3x - 12)$

$\longrightarrow \tt 4x + 20 = 6x - 24$

$\longrightarrow \tt 4x - 6x = -24- 20$

$\longrightarrow \tt - 2x = - 44$

$\longrightarrow \tt x = \dfrac{-44}{-2\;}$

$\longrightarrow {\purple{\underline{\boxed{\pmb{\frak{ x = 22 }}}}\bigstar}}$

~ Now let's find the total number of students :

$\longrightarrow \textbf { Total No of students = 3x + 4x }$

$\longrightarrow \textbf { Total No of students = 3(22) + 4 (22) }$

$\longrightarrow \textbf { Total No of students 66 + 88 }$

$\longrightarrow \textbf { Total No of students = 154 }$

Hence:

• The total number of students in the class  are 154

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