Question

$\bf Question \: -$

⇝ usha swims in a 90m long pool she covers 180m in one minute by swimming from one end to the other and back along the same straight path. find the average speed and average velocity of usha ??​

Answer 1

Given :- Here, it is given that Usha swims in an 90 m long pool. If she can swim 180 m in one minute from one end to another and back along the same straight path, we should find the average speed and average velocity of Usha.

To Find :- In the given question, we have to find the average velocity and average speed of Usha.

Solution :- To find the average speed of Usha, we will,

Average speed = $\sf\dfrac{Total \ distance}{Total \ time \ taken}$

Average speed = $\sf\dfrac{180}{1 min = 60 sec}$

Average speed = $\sf\dfrac{180}{60}$

Average speed = 3 m/s

• Hence, average speed of Usha will be 3 m/s.

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Now, to find average velocity of Usha, we will,

Average velocity = $\sf\dfrac{Displacement}{Time \ taken}$

Here, we know that, displacement covered by Usha is 0.

Average velocity = $\sf\dfrac{0}{60}$

Average velocity = 0 m/s

• Hence, average velocity of Usha will be 0 m/s.

$\qquad \qquad \qquad \qquad {\mathtt{Thanks !!}} $