Question

$\binom{ \sqrt{3 + \sqrt{2} } }{ \sqrt{3 - \sqrt{2 } } } = a + b \sqrt{2}$
find the value of a and b in this​

Answer 1

Answer:

Therefore,a=5 and b=2√3

Step-by-step explanation:

=√3+√2/√3-√2

Multiply and divide by √3+√2

=[√3+√2]^2/(√3)^2-(√2)^2

=3+2+2√6/3-2

=5+2√6/1

=5+2√6=a+b√2

=5+2√3×√2=a+b√2

By comparing

we will get a=5,b=2√3