Question

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The 17th term of an ap exceeds its 10th term by 7 find the common difference.​

Answer 1

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We know that, for an A.P series

an = a+(n−1)d

a17 = a+(17−1)d

a17 = a +16d

In the same way,

a10 = a+9d

As it is given in the question,

a17 − a10 = 7

Therefore,

(a +16d)−(a+9d) = 7

7d = 7

d = 1

Therefore, the common difference is 1.

Answer 2

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