Question

$\blue{\bold{\underline{\underline{Solve it:-}}}}$ ​

Answer 1

Answer:

$<p style="color:cyan;font-family:cursive;background:black;font size:25px;"> I have attached above the solution .$

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Answer 2

Step-by-step explanation:

$\sf{\bold{\blue{\underline{\underline{Given}}}}}$

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☆$\dfrac{1}{3}rd$ in mud.

☆$\dfrac{ 1}{4}th$ in water.

$\sf{\bold{\red{\underline{\underline{To\:Find}}}}}$

⭐Lenth of the bamboo??⠀⠀⠀⠀

$\sf{\bold{\purple{\underline{\underline{Solution}}}}}$

Let,the length of bamboo=x

so,

The part lied in mud=$\dfrac{1}{3}th=\dfrac{x}{3}m.$

Similarly,

Part inthe water=$\dfrac{1}{4}th=\dfrac{x}{4}m.$

So,

Total part in the mud and water=$\dfrac{x}{3}+\dfrac{x}{3}$

$\rightsquigarrow{\dfrac{4x+3x}{12}}$

$\rightsquigarrow{\dfrac{7x}{12}}$

According to the question,

5 metres are above water.

so....,

$\rightsquigarrow$ $\dfrac{7x}{12}+5=x$

$\rightsquigarrow$ $\dfrac{7x}{12}=x-5$

$\rightsquigarrow$ $\tt{12(x-5)=7x}$

$\rightsquigarrow$ $\tt{12x-60=7x}$

$\rightsquigarrow$ $\tt{12x-7x=60}$

$\rightsquigarrow$ $\tt{5x=60}$

$\rightsquigarrow$ $\tt{x=\dfrac{60}{5}}$

$\rightsquigarrow$ $\tt{x=12}$

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

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Length of bamboo is 12cm