Question

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Answer 1

ANSWER

CONCEPT

Pythagoras theorem

SOLUTION

Let length of PQ be h

IN ∆ PQM

h^2 = y^2 - 9 .......... 1

IN ∆ PQR

h^2 = x^2 - (3+2) ^2........ 2

from 1 and 2

y^2 - 9 = x^2 - (5) ^2

x^2 - y^2 = 25 -9 = 16

=> 16

Answer 2

hthe answer is this.. nus nus