Answers
Answered by
2
PROFE THAT A^0 = 1
A^0 = 1
A^0 = A^(1-1)
A^0 = [A^1]×[A^(-1)]
A^0 = A × (1/A) [ SINCE A^1 = A AND A^(-1) = 1/A]
A^O = A/A
A^O = 1
HENCE, IT IS PROVED
Answered by
1
Hope it helps uh✌️
Similar questions