Question

A constant force acting on a body of mass3.0 kg change its speed from 2.0m/s to 3.5m/s in 25s. the direction of the motion of the body remains unchanged.what is the magnitude of the Force?​

Answer 1

Answer:

Mass (m) = 3 kg

Initial velocity (u) = 2m/s

Final velocity (v) = 3.5 m/s

Time (t) = 25s

v = u + at

3.5 = 2 +a(25)

25a = 1.5

a = 0.06 m/s²

F = ma

F = 3 × 0.06

F = 0.18 N

Answer 2

Answer:-

F = 0.18 N

Given :-

$m = 3kg \\ u = 2 m/s \\v = 3.5 m/s \\ t = 25 s$

To find :-

Magnitude of the force.

Solution:-

• First we have to find the acceleration produced by the constant force.

• Using first equation of motion.

→$v = u + at$

→$3.5 = 2 + a \times25$

→$3.5-2 = 25a$

→$1.5 = 25 a$

→$a = \dfrac{1.5}{25}$

→$a = 0.06 m/s^2$

hence,

Acceleration produced by the force is 0.06 m/s².

Magnitude of constant force is given by :-

• Using newton 2nd law.

→$F = ma$

• Put the given values,

→$F = 3 \times \dfrac{6}{100}$

→$F = \dfrac{18}{100}$

→$F = 0.18 N$

hence,

Magnitude of constant force is 0.18 N.