Question

$\bold\purple{A\: solid\: is\: in\: the\: form \:of \:a\: right \:circular\: cylinder\: with\: a \:hemisphere\: one\: end \:and \:a cone\: at\: the\: other\: end\:. The \:radius\: of \:the\: common \:base\: is\: 8 cm.\: and\: the \:heights\: of\: the\: cylindrical \:and\: conical\: portion\: are \:10 cm\: and\: 6 cm\: respectively.\: Find\: the \:total\: surface\: area\: of\: the \:solid.\ \textless \ br /\ \textgreater \ (use π = 3.14)}$

$\color{red}\huge\bold{heyy\: please}$

Answer 1

CSA of cylinder = 2 pie r h

= 2 pie × 8 × 10

= 160 pie

Area of hemisphere = 2pie r^2

= 2 pie 8^2

= 128 pie

CSA of conical= pie r l

= pie r √ H^2 + r^2

= pie × 8 √ 36 + 64

= 80 pie

TSA of solid =160+ 128 +80) pie
= 1155.52 cm^2