Math, asked by sk181231, 7 months ago

\bold\red{QueSTioN}


\sf{ Half \: the \: perimeter \: of \: a \: rectangular \: // garden \: , \: Whose \: length \: is \: 4m \: more  \: than \: // it's \: width , is \: 36m . \: Find \: the \: // dimension \: of \: garden }

Answers

Answered by MysteriousAryan
26

\huge\bf { AnSwer }

Let the width of the garden =x m

Then length=(x+4) m

Half perimeter =36 m

So perimeter of garden =(2×36)=72 meters

According to the question

⇒2(l+b)=72

⇒2(x+x+4)=72

⇒2x+2x+4=74

⇒4x=64

⇒x=16 meters

Hence,the width of the garden =16 meters

The length of the garden =(16+4)=20 meters

Answered by Anonymous
4

Answer:

Let the width of the garden =x m

Then length=(x+4) m

Half perimeter =36 m

So perimeter of garden =(2×36)=72 meters

According to the question

⇒2(l+b)=72

⇒2(x+x+4)=72

⇒2x+2x+4=74

⇒4x=64

⇒x=16 meters

Hence,the width of the garden =16 meters

The length of the garden =(16+4)=20 meters

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