Question

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A bullet of mass 25g strikes a wooden target with the velocity of 100 m/s and emerges with the velocity of 20 m/s. Find the loss in energy during the process of penetration.
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Answer 1

Answer:

hope so it helps you dear

Answer 2

Answer:

Explanation:

Given :

• Mass of a bullet (m) = 25 g ⇒ 0.025 kg
• Initial velocity (u) = 100 m/s
• Final velocity (v) = 20 m/s

To Find :

• The loss in energy during the process of penetration.

Formula to be used :

• K.E = 1/2 × mu² and K.E = 1/2 × mv².

Solution :

★Initial kinetic energy,

K.Eᵢ = 1/2 × mu²

⇒ K.Eᵢ = 1/2 × 0.025 × (100)²

⇒ K.Eᵢ = 0.5 × 0.025 × 10000

⇒K.Eᵢ = 125 J

★Final kinetic energy,

K.Eբ = 1/2 × mv²

⇒ K.Eբ= 1/2 × 0.025 × (20)²

⇒ K.Eբ = 0.5 × 0.025 × 400

⇒K.Eբ = 5 J

★Loss in kinetic energy,

K.Eᵢ - K.Eբ

⇒ 125 - 5

⇒ 120 J

Hence, The loss in energy during the process of penetration is 120 J.