Chemistry, asked by Shinzo16, 7 hours ago


calculate \: the \: number \: of \:
molecules \: in \: a \: drop \: of \:
water \: weighing \: 0.048 \: g
Concept : Mole

Answers

Answered by shashikanthkumar896
0

Answer:

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Answered by CopyThat
6

Answer:

  • 1.606 × 10²¹ molecules.

Explanation:

We know:

\bold{H_{2}O\;weight\;=2(1)+16=18g.}

\bold{18 g \;of \;H_{2}O\;contains\;6.022\times10^{23}\;molecules.}

To find:

\bold{Number\;of\;molecules\;in\;0.048g\;of\;H_{2}O.}

Solution:

\bold{18g\;-\;6.022 \times 10^{23} \; molecules.}

\bold{0.048g \;-\;?\;molecules.}

  • 18x = 6.022 × 10²³ × 0.048
  • x = 6.022 × 10²³ × 0.048/18
  • x = 0.289104 × 10²³/18
  • x = 0.01606 × 10²³
  • x = 1.606 × 10²¹

∴ There are 1.606 × 10²¹ molecules in one drop of water weighing 0.048 g.

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