Question

$(CH_{3})_{3}N$ is basic but $(CF_{3})_{3}N$ is not basic. Explain.

Answer 1

       Basicity can be accounted by the electron availability, in the case of $(C{ H }_{ 3 }{ ) }_{ 3 }N$ is more electron availability than $(C{ F }_{ 3 }{ ) }_{ 3 }N$.   This is due to various atoms like H and F electronegative ions connected with nitrogen.

      The lone pair of N in $(C{ H }_{ 3 }{ ) }_{ 3 }N$ is concentrated on N and either can act as an electron pair donor (Lewis base).

      However in $(C{ F }_{ 3 }{ ) }_{ 3 }N$ have less electron density on N because F atom attached is to C, and it is highly electronegative therefore it can be act as a Lewis base.

      Hence,  $(C{ H }_{ 3 }{ ) }_{ 3 }N$ is basic and $(C{ F }_{ 3 }{ ) }_{ 3 }N$ is not basic.