Question

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9x^y^(3x-24)3/27xy(z-8)​

Answer 1

Answer:

☺️☺️

9x²y²(3z-24)/27xy(z-8)

⇒27x²y²z-216x²y²/27xyz-216xy

⇒27x²y²(z-8)/27xy(z-8)

⇒every thing gets cancelled and finally

xy remains

⇒xy

Answer 2

Answer:

$9 {x}^{2} {y}^{2} (3z-24)\div 27xy(z - 8) \\ = 27x^{2} y ^{2} z -216 {x}^{2}y {}^{2} \div 27xyz - 216xy \\ = 27x {}^{2} y {}^{2} (z - 8) \div 27xy(z - 8) \\ = xy$

So, the answer is 'xy'.

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