![compare \sqrt[6]{15 \:} \: \: and \: \: \sqrt[4]{12} compare \sqrt[6]{15 \:} \: \: and \: \: \sqrt[4]{12}](https://tex.z-dn.net/?f=compare+%5Csqrt%5B6%5D%7B15+%5C%3A%7D++%5C%3A++%5C%3A+and+%5C%3A++%5C%3A++%5Csqrt%5B4%5D%7B12%7D+)
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Answer:
4√12 > 6√15
Step-by-step explanation:
6√15 = (15)^1/6 & 4√12 = (12)^1/4
LCM (6,4) = 24 , LCM (12,15) = 60
(60)^24/6 = (60)^4 , (60)^24/4 = (60)^6
60^6 > 60^4
hence. 4√12 > 6√15
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