Question

$\cos(23 ) - \sin(67) \div \tan(26) \times \tan(64) =$
​

Answer 1

Given :   {Cos(23°) - Sin(67°) }/ ( tan26 * tan64)

To Find  : Value

Solution:

{Cos(23°) - Sin(67°) }/ ( tan26° * tan64°)

tan26° * tan64°  = tan 26° * cot (90° - 64°)

= tan 26° * cot (26°)

=tan 26°/tan 26°

= 1

Sin(67°) = Cos(90° - 67°) = Cos(23°)

{Cos(23°) - Sin(67°) }/ ( tan26° * tan64°)

= ( Cos(23°) -  Cos(23°))/1

= 0/1

= 0

{Cos(23°) - Sin(67°) }/ ( tan26° * tan64°)  = 0

Learn More:

sin4x+sin3x+sin2x/cos4x+cos3x+cos2x

brainly.in/question/8661724

Prove that: (sin3x+sinx)sinx+(cos3x-cosx)

brainly.in/question/6631850

Answer 2

Answer :-

{Cos(23°) - Sin(67°) }/ ( tan26° * tan64°)

tan26° * tan64°  = tan 26° * cot (90° - 64°)

= tan 26° * cot (26°)

=tan 26°/tan 26°

= 1

Sin(67°) = Cos(90° - 67°) = Cos(23°)

{Cos(23°) - Sin(67°) }/ ( tan26° * tan64°)

= ( Cos(23°) -  Cos(23°))/1

= 0/1

= 0

{Cos(23°) - Sin(67°) }/ ( tan26° * tan64°)  = 0