Question

$\cos(e ) \1 - \sin(e) + 1 - \sin(e) \ \cos(e) = 2 \sec(e)$
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Answer 1

Step-by-step explanation:

cose/1-sine + 1-sine/cose

=cos²e+(1-sine)²/cose(1-sine)

=cos²e+1+sin²e-2sine/cose(1-sine)

=2-2sine/cose(1-sine)

=2(1-sine)/cose(1-sine)

=2/cose

=2sece