Math, asked by raja1663, 9 months ago


cosx \div 1 +  \sin ^{2} (x) dx
solve the problem

Answers

Answered by classofankur
1

Step-by-step explanation:

cosx/ 1+sin²x dx

taking sinx = t

cosx dx = dt

=cosx/ 1+t² cosx dt

=1/ 1+t² dt

= tan inverse t

= tan inverse sinx.

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