Question

$((csc(x) - cot(x) ) \div \sin(x) ) = 1 \div (1 + \cos(x) )$
​

Answer 1

$\frac{cosecx - cotx}{sinx} \\ = \frac{ \frac{1 - cosx}{sinx} }{sinx} \\ = \frac{1 - cosx}{ {sin}^{2}x } \\ = \frac{1 - cosx}{1 - {cos}^{2} x} \\ = \frac{1}{1 + cosx}$