Question

$f(x) = \sqrt{3 - 2x}$
find domain and range of the function.

Answer 1

Solution is attached here

Answer 2

Given:

f(x) = $\sqrt{3 - 2x}$

To Find:

the domain and range f(x).

Solution:

The Domain of f(x)

    3 -2x ≥ 0

    3 ≥ 2x

    $\frac{3}{2}$ ≥ x

    x ≤ $\frac{3}{2}$

Domain of f(x)= (-∞, $\frac{3}{2}$)

The range of f(x),

    Let y be f(x)

                        y = f(x)

                        y = $\sqrt{3 - 2x}$

Since 3- 2x ≥ 0

          y ≥ 0

Range of f(x) = (0, ∞)

Therefore, domain of f(x)= (-∞, $\frac{3}{2}$) and range of f(x)= (0, ∞).