Question

$f(x) = {x + x}^{2} find \: f(1) + f(0)$

Answer 1

✳ Answer ✳


⏬⏬⏬⏬

Given F(1)

=1+1^2
=1+1
=2


Given F(0)


=0+0^2
=0+0
=0

Answer 2

$\bf\huge\color{red}\texttt{ hello\: mate!}$

Since, $\bf{f(x) = {x + (x)}^{2}}$

so , if $\bf{x = 1}$ , then,

$\bf{ f(1) = {1 + (1)}^{2}}$

make square of the digit inside the bracket , i.e., 1² = 1

$\bf{ f(1) = 1+1}$

add the digits!

$\bf{ f(1) = 2}$

now ,

if $\bf{ x = 0}$ , then ,

$\bf{ f(0) = {0 + (0)}^{2}}$

make square of the digit inside the bracket , i.e., 0² = 0

$\bf{ f(0) = 0 + 0}$

add the digits!

$\bf{ f(0) = 0}$

hence,

$\bf{ f(1) + f(0)}$

Substitute their values as we found above that f(1) = 2 and f(0) = 0.

= $\bf{ 2 + 0}$

= $\bf{ 2 }$ [ANSWER]