Question

$factorise\: the \: equation \: \binom{1}{3} x ^{2} - 2x - 9$
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Answer 1

Answer:

$= > \frac{1}{3} {x}^{2} - 2x - 9 \\ \\ = > \frac{1}{3} {x}^{2} - (3 - 1)x - 9 \\ \\ = > \frac{1}{3} {x}^{2} - 3x + x - 9 \\ \\ = > \frac{1}{3} x(x - 9) + 1(x - 9) \\ \\ = > (x - 9)( \frac{1}{3} x + 1)$

Answer 2

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