Question

$find \: the \: continued \: product \: (2x + 3y) \: (2x - 3y) \: (4x {}^{2} + 9y {}^{2})$

Answer 1

Let f(x) = (2x + 3y).(2x - 3y).(4x^2 + 9y^2)
f(x) = [(2x)^2 - (3y)^2].(4x^2 + 9y^2) [since (a-b).(a+b) = (a^2 - b^2)]
f(x) = (4x^2 - 9y^2).(4x^2 + 9y^2)
=>f(x) = [(4x^2)^2 - (9y^2)^2]
=>f(x) = (16x^4 - 81y^4)

Therefore the result is (16x^4 - 81y^4)
Hope this helps you :)

Answer 2

Step-by-step explanation:

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