Math, asked by tarunpala43, 23 hours ago

find \: the \: derivative \: of \: \frac{ {a}^{2} }{16\pi} + \frac{ {a}^{2} }{64}

Answers

Answered by jaswasri2006
0

 \int \frac{ {a}^{2} }{16\pi}  +  \frac{ {a}^{2} }{64\pi}  =  \int \frac{ {a}^{2} }{16\pi} (1 +  \frac{1}{4} )

Answered by itzbrainlycommando13
2

 \int \frac{ {a}^{2} }{16\pi} (1 +  \frac{1}{4} )

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