Question

$find \: the \: value \: of \: x \: if { \sqrt{3} }^{x} = {3}^{7}$
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Answer 1

${ \sqrt{3} }^{x} = {3}^{7} \\ = > {3}^{x \times \frac{1}{2} } = {3}^{7} \\ on \: comparing \\ = > \frac{x}{2} = 7 \\ = > x = 7 \times 2 \\ = > x = 14$

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