Math, asked by scs303611, 11 months ago


 \frac{1}{2 -  \sqrt{3} }  -  \frac{1}{ \sqrt{3}  +  \sqrt{2} }  +  \frac{4}{3 -  \sqrt{5} }

Answers

Answered by eashgupta644
31

Answer:

\frac{1}{2 - \sqrt{3} } - \frac{1}{ \sqrt{3} + \sqrt{2} } + \frac{4}{3 - \sqrt{5} }

Hope this helps you

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Answered by Anonymous
16

 \huge{ \purple{ \bigstar{ \mathfrak{answer♡</p><p>}}}}

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 \frac{1}{2 -  \sqrt{3} }  - \frac{1}{ \sqrt{3} +  \sqrt{2}  }  +  \frac{4}{3 -  \sqrt{4} }

 \frac{1}{2 -  \sqrt{3} } \times  \frac{2 +  \sqrt{3} }{2 +  \sqrt{3} }  -   \frac{1}{ \sqrt{3} +  \sqrt{2}  }   \times  \frac{ \sqrt{3}  -  \sqrt{2} }{ \sqrt{3} -  \sqrt{2}  }  +  \frac{4}{3 -  \sqrt{5} }  \times  \frac{3 +  \sqrt{5} }{3 +  \sqrt{5} }

  \frac{2 +  \sqrt{3} }{4 - 3}  -  \frac{ \sqrt{3}  -  \sqrt{2} }{3 - 2}  +  \frac{12 + 4 \sqrt{5} }{9 - 5}

2 +  \sqrt{3}  -  \sqrt{3}  -  \sqrt{2}  +  \frac{4(3 +  \sqrt{5} )}{4}  \\

{ \boxed{ \green{ \underline{ \mathfrak{answer = 5 -  \sqrt{10} }}}}}

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hops this may help you

 \huge{ \red{ \ddot{ \smile}}}

 \huge \blue{ \mathfrak{thanks♡</p><p>}}

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