Question

$\frac{1}{4} \div ( \frac{3}{4} - \frac{1}{2}) + 2\frac{1}{6} \times \frac{1}{2}$
Solve this problem please​

Answer 1

The answer is 25/12 mark me brainlist

Answer 2

Correct Question-:

• Simplify -: $\sf{\dfrac{1}{4} \div ( \dfrac{3}{4} - \dfrac{1}{2}) + 2\dfrac{1}{6} \times \dfrac{1}{2}}$

AnswEr-:

• $\boxed{\sf {Answer\:= \dfrac{25}{12} }}$

EXPLANATION-:

• $\dag{\sf{\large { Solution-:\:}}}$

• $\implies{\sf{\large {\dfrac{1}{4} \div ( \dfrac{3}{4} - \dfrac{1}{2}) + 2\dfrac{1}{6} \times \dfrac{1}{2}}}}$

• $\implies{\sf {\dfrac{1}{4} \div ( \dfrac{3}{4} - \dfrac{1}{2}) + \dfrac{13}{6} \times \dfrac{1}{2}}}$

• $\star{\sf{\large { LCM\:of\:2\:and\:4-:\:4}}}$

• $\implies{\sf {\dfrac{1}{4} \div \dfrac{(3-2)}{4} + \dfrac{13}{6} \times \dfrac{1}{2}}}$

• $\implies{\sf {\dfrac{1}{4} \div \dfrac{1}{4} + \dfrac{13\times 1}{6\times 2} }}$

• $\implies{\sf {\dfrac{1}{4} \div \dfrac{1}{4} + \dfrac{13}{12} }}$

• $\implies{\sf {\dfrac{1}{4} \div \dfrac{1}{4} + \dfrac{13}{12} }}$

• $\star{\sf{\large { Reciprocal\:of\:\dfrac{1}{4}\:=\:\dfrac{4}{1}}}}$

• $\implies{\sf {\dfrac{1}{4} \times \dfrac{4}{1} + \dfrac{13}{12} }}$

• $\implies{\sf {1 + \dfrac{13}{12} }}$

• $\dag{\sf{\large { Or,\:}}}$

• $\implies{\sf {\dfrac{1}{1} + \dfrac{13}{12} }}$

• $\star{\sf{\large { LCM\:of\:12\:and\:1-:\:12}}}$

• $\implies{\sf { \dfrac{12 + 13}{12} }}$

• $\implies{\sf { \dfrac{25}{12} }}$

• $\implies{\sf {Answer\:= \dfrac{25}{12} }}$

Hence ,

• $\boxed{\sf {Answer\:= \dfrac{25}{12} }}$

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