Question

$\frac{1}{9} x {}^{2} - \frac{2}{3} x + 1 = 0$
Find the ROOT of the following equation using FACTORIZATION METHOD ​

Answer 1

Answer:

1/9x²-2/3x+1=0

1/9x²-1/3x-1/3x+1=0

1/3x(1/3x-1)-1(1/3x-1)

(1/3x-1)(1/3x-1)

x=1/3 0r x=1/3

Answer 2

Answer:

Given : (4/x) - 3 = 5/(2x + 3)

[4 - 3x]/x = 5/(2x + 3)

[By taking LCM]

(4-3x) (2x + 3) = 5x

8x +12 - 6x² - 9x = 5x -6x² + 8x - 9x - 5x+12 = 0

-6x² - 6x + 12 = 0

-6(x² + x - 2) = 0

x²+x-2=0

x² + 2x - x - 2 = 0

x(x + 2)-1(x+2) = 0

(x-1)(x+2) = 0

x-1=0 or x + 2 = 0

x = 1 or x = -2

x-1=0 or x+2=0

x = 1 or x = -2

Hence, the roots of the quadratic equation (4/x) - = 5/(2x + 3) are 1 & -2.

✰✰ METHOD TO FIND SOLUTION OF a quadratic equation by FACTORIZATION METHOD:

 ${\huge{\boxed{\mathcal{\Green{Gd mrng}}}}}$