Question

$\frac{1 \: + \: \: tan \: {}^{2} }{ \: 1 \: + \: cot {}^{2} } - \: \frac{sec {}^{2} }{cosec {}^{2} } = \: 0$
Prove the statement

Answer 1

HOLA

=================

$1 \: + \: tan {}^{2} = \: sec {}^{2} \\ \\ 1 \: + \: cot {}^{2} = \: cosec {}^{2} \\ \\ \\ \frac{sec {}^{2} }{cosec {}^{2} } - \: \frac{sec {}^{2} }{cosec {}^{2} } = \: 0$

====================

HOPE U UNDERSTAND ❤❤❤

Answer 2

Hope it will help u...