Question

$\frac{1-tan^{2}45^{0} }{1+tan^{2}45^{0}}$ is equal to
(a)tan 90°
(b)1
(c)sin 45°
(d)sin 0°

Answer 1

SOLUTION :  

The correct option is (d) : sin 0°

Given : 1 - tan² 45° / 1 +  tan² 45°

1 - tan² 45° / 1 +  tan² 45°

= 1 - (1)² / 1 + (1)²

[tan 45° = 1]

= 1 - 1 / 1 + 1

= 0/2

= 0  

= sin 0°         [ sin 0° = 0]

Hence, the value of 1 - tan² 45° / 1 +  tan² 45° is sin 0° .

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Answer 2

d) sin0° = 0 is correct