Question

$\frac{18x^{5} }{4xy}$×$\frac{2y^{3} }{6x^{2} }$ ÷$\frac{3x^{4}y^{2} }{2x^{2} }$
simplify the fraction.

Answer 1

⇨ 1

$\frac{18 {x}^{5} }{4xy} \times ( \frac{2 {y}^{3} }{6 {x}^{2} } \: \div \frac{3 {x}^{4} {y}^{2} }{2 {x}^{2} } ) \:$

$\frac{18 {x}^{5} }{4xy} ( \frac{2 {y}^{3} }{6 {x}^{2} } \times \frac{2 {x}^{2} }{3 {x}^{4} {y}^{2} } )$

$can \: solve \: in \: the \: brakets \: or \: can \: open \: the \: brackets \: also$

$\frac{18 {x}^{5} }{4xy} \times \frac{2y}{6} \times \frac{2}{3 {x}^{4} }$

$\frac{18x}{4xy} \times \frac{2y}{3} \times \frac{1}{3}$

$\frac{36xy}{36xy}$

$\frac{1}{1}$

$1$

U'll get it mate, give it a closure look .

Have a good day :)

Answer 2

Answer:

hey ur answer is in attechment pic so watch it.