Question

$\frac{2 \sqrt{3} + 6 }{\sqrt{3}} \times \frac{ \sqrt{3}}{ \sqrt{3} }$


$\huge\red{please \ explain \ this}$​

Answer 1

$\dfrac{2 \sqrt{3} + 6 }{ \sqrt{3} }\times \dfrac{ \sqrt{3}}{ \sqrt{3} }$

$= \dfrac{2 \times 3 + 6 \sqrt{3} }{3} = \dfrac{6 + 6 \sqrt{3} }{3}$

$= \dfrac{ \bcancel{ 3}(2 + 2 \sqrt{3} )}{ \bcancel{3} } = \boxed{2 + 2 \sqrt{3}}$

Answer 2

answers wright diye hai na

cell is fundamental structure and function unit is called cell. hope it's helpful