Question

$(\frac{2a}{3} + \frac{3b}{4}) {}^{2}$
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Answer 1

Step-by-step explanation:

${( \frac{2a}{3} + \frac{3b}{4} )}^{2 }$

(2a)^2/3^2 + 2 ( 2a/3 * 3b/4) +(3b)^2/4^2

4a^2/9 + 2 * 6ab/12 + 9b^2/ 16

4a^2/9 + 6ab/6 + 9b^2/ 16

4a^2/9 + ab + 9b^2/16