Question

$\frac{2a}{ {a}^{2} - 1} + \frac{5a}{ {a}^{2}3a + 2 }$
परिमेय व्यंजक युगमो का योग ज्ञात कीजिए

Answer 1

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$\bold{\underline{Question-}}$


$\frac{2a}{ {a}^{2} - 1} + \frac{5a}{ {a}^{2}3a + 2 }$
परिमेय व्यंजक युगमो का योग ज्ञात कीजिए




$\bold{\underline{Answer-}}$

$\frac{2a}{ {a}^{2} - 1} + \frac{5a}{ {a}^{2}3a + 2 }$


$= > \frac{2a}{(a - 1)(a + 1)} + \frac{5a}{ (a - 1)(a - 2)} \\ \\ \\ = > \frac{2a(a - 2) + 5a(a + 1)}{(a - 1)(a + 1)(a - 2)} \\ \\ \\ \\ = > \frac{ {2a}^{2} - 4a + {5a}^{2} + 5a}{(a - 1)(a + 1)(a - 2)} \\ \\ \\ \\ = > \frac{ {7a}^{2} + a }{(a - 1)(a + )(a - 2)} \\ \\ \\ \\ = > \frac{a(7a + 1)}{(a - 1)(a +1 )(a - 2)}$

Answer 2

a2−12a​+a23a+25a​ 

$\begin{lgathered}= > \frac{2a}{(a - 1)(a + 1)} + \frac{5a}{ (a - 1)(a - 2)} \\ \\ \\ = > \frac{2a(a - 2) + 5a(a + 1)}{(a - 1)(a + 1)(a - 2)} \\ \\ \\ \\ = > \frac{ {2a}^{2} - 4a + {5a}^{2} + 5a}{(a - 1)(a + 1)(a - 2)} \\ \\ \\ \\ = > \frac{ {7a}^{2} + a }{(a - 1)(a + )(a - 2)} \\ \\ \\ \\ = > \frac{a(7a + 1)}{(a - 1)(a +1 )(a - 2)}\end{lgathered}=>(a−1)(a+1)2a​+(a−1)(a−2)5a​=>(a−1)(a+1)(a−2)2a(a−2)+5a(a+1)​=>(a−1)(a+1)(a−2)2a2−4a+5a2+5a​=>(a−1)(a+)(a−2)7a2+a​=>(a−1)(a+1)(a−2)a(7a+1)​​$