Question

$\frac{2p + 1}{3} + \frac{p - 1}{2} = 4 \times \frac{1}{2}$
​

Answer 1

$\frac{2p + 1}{3} + \frac{p - 1}{2} = 4 \times \frac{1}{2}$

$\frac{4p + 2 + 3p - 3}{6} = 2$

$7p - 1 = 12$

$7p = 12 + 1$

$7p = 13$

$p = \frac{13}{7}$

Answer 2

3

2p+1

+

2

p−1

=4×

2

1

\frac{4p + 2 + 3p - 3}{6} = 2

6

4p+2+3p−3

=2

7p - 1 = 127p−1=12

7p = 12 + 17p=12+1

7p = 137p=13

p = \frac{13}{7}p=

7

13