Question

$\frac{2x - 1}{3} - \frac{6x - 2}{5} = \frac{1}{3}$

Answer 1

Hii friend,

=> 2X-1/3 - 6X-2/5 = 1/3

=> 5(2X-1) -3(6X-2)/15 = 1/3

=> 10X -5 -18X +6 /15 = 1/3

=> -8X +1 /15 = 1/3


=> 3(-8X+1) = 15

=> -24X +3 = 15

=> -24X = 15-3

=> X = 12/-24

=> X = -1/2


HOPE IT WILL HELP YOU.... :-)

Answer 2

Hey friend,
Here is the answer you were looking for:

$\frac{2x - 1}{3} - \frac{6x - 2}{5} = \frac{1}{3} \\ \\ \frac{5(2x - 1) - 3(6x - 2)}{15} = \frac{1}{3} \\ \\ \frac{2x \times 5 - 1 \times 5 - 6x \times 3 + 2 \times 3}{15} = \frac{1}{3} \\ \\ \frac{10x - 5 - 18x + 6}{15} = \frac{1}{3} \\ \\ \frac{ - 8x + 1}{15} \\ \\ on \: cross \: multiplying \: we \: get \\ \\ 3( - 8x + 1) = 15 \\ \\ - 24x + 3 = 15 \\ \\ - 24x = 15 - 3 \\ \\ - 24x = 12 \\ \\ x = \frac{ 12}{ - 24} \\ \\ x =- \frac{1}{2}$

Hope this helps!!!

If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.

@Mahak24

Thanks...
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