Question

$( \frac{3m}{2} + \frac{2n}{3})( \frac{3m}{2} - \frac{2n}{3} ) =$
plz Answer the Question ​

Answer 1

Answer:

$\frac{81m^2-16n^2}{36}$

Step-by-step explanation:

$(\frac{3m}{2} +\frac{2n}{3}) (\frac{3m}{2} -\frac{2n}{3})$

= $(\frac{3m}{2})^{2} -(\frac{2n}{3})^2$                                [As a²-b²=(a+b)(a-b)]

= $\frac{9m^2}{4}-\frac{4n^2}{9}$

= $\frac{81m^2-16n^2}{36}$

Ans:- $\frac{81m^2-16n^2}{36}$

Answer 2

Answer:

$( \frac{3m}{2} + \frac{2n}{3})( \frac{3m}{2} - \frac{2n}{3} )$

$( \frac{9m}{6} + \frac{4n}{6})( \frac{9m}{6} - \frac{4n}{6} )$

$( \frac{9m + 4n}{6})( \frac{9m - 4n}{6} )$

$\frac{(9m + 4n)(9m - 4n)}{36}$

$\frac{9m (9m - 4n) + 4n(9m - 4n)}{36}$

$\frac{81 {m}^{2} - 36mn + 36mn - 16 {n}^{2} }{36}$

$\frac{81 {m}^{2} - 16 {n}^{2} }{36}$

I think it is the answer