Question

$\frac{3t - 2}{4} - \frac{2t + 3}{3} = \frac{2}{3} - t$
Linear Equation

Answer 1

$\frac{3t - 2}{4} - \frac{2t + 3}{3} = \frac{2}{3} - t \\ \\ \\ \\ \longrightarrow \: \frac{3(3t - 2) - 4(2t + 3)}{12} = \frac{2 - 3t}{3} \\ \\ \\ \longrightarrow3(9t - 6 - 8t - 12) = 12(2 - 3t) \\ \\ \\ = > 3 \times 1(9t - 8t - 12 - 6) = 3 \times 4(2 - 3t) \\ \\ \\ \longrightarrow \: 1(t - 18) = 4(2 - 3t) \\ \\ \\ = > t - 18 = 8 - 12t$

=> - 18 - 8 = -12t - t

=> - 26 = - 13t

=> 26 = 13t

$= > \frac{26}{13}= t$

=> 2 = t





$\textbf{ value of t is 2}$

Answer 2

$Answer : \boxed{2}}$

Hope this helps!