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1
Answer:
x
2
−7x+12
3x
2
−x−2
÷
x
2
−4
3x
2
−7x−6
(∵
B
A
÷
D
C
=
B
A
×
C
D
) and A
2
−B
2
=(A−B)(A+B)
⇒
x
2
−7x+12
3x
2
−x−2
×
3x
2
−7x−6
x
2
−4
⇒
(x−3)(x−4)
(3x+2)(x−1)
×
(3x+2)(x−3)
(x−2)(x+2)
⇒
(x−3)
2
(x−4)
(x−1)(x−2)(x+2)
.
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