Math, asked by LilyWhite, 9 months ago

$\frac{{3x}^{3}{-}{7x}^{2}{-}{7x}{+}{3}}{x~+~1}$

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Answered by SassyWendy

8

Answer:

$\frac{ {3x}^{3} - 7x {}^{2} - 7x + 3 }{x + 1} \\ \\ \frac{ {3x}^{3} + 3 - {7x}^{2} - 7x }{x + 1} \\ \\ \frac{3( {x}^{3} + 1) - 7x( x + 1) }{x + 1} \\ \\ \frac{3(x + 1)( {x}^{2} - x + 1) - 7x(x + 1)}{x + 1} \\ \\ 3( {x}^{2} - x + 1) - 7x \\ \\ 3 {x}^{2} - 10x + 3 \\ \\ {3x}^{2} - 9x -x + 3 \\ \\ x = 1 \\ \\ x = 3$

Answered by ItzSarcasm

11

Answer:

See below :-

Step-by-step explanation:

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♥ 3x³ - 7x² - 7x + 3 / x + 1

♥ 3x³ + 3 - 7x - 7x / x + 1

♥ 3 ( x³ + 1 ) - 7x ( x + 1 ) / x + 1

♥ 3 ( x + 1 ) ( x² - x + 1 ) - 7x ( x + 1 ) / x + 1

♥ 3 ( x² - x + 1 ) - 7x

♥ 3x² - 10x + 3

♥ 3x² - 9x - x + 3

❣ x = 1
❣ x = 3

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