Question

$( \frac{4}{?3} {x}^{2} yz) \times ( \frac{1}{3?} zx) \times ( - 6 xy{?z}^{2} )$
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Answer 1

$\rm \large \bigg( \frac{4}{3} {x}^{2} yz \bigg)\times \frac{1}{ \cancel3} zx \times \bigg( - \cancel6xy {z}^{2} \bigg) \\ \\ \tt= > \frac{4}{3} {x}^{2}yz \times 1(zx) \times - 2xy {z}^{2} \\ \\ = \tt > {x}^{4} {y}^{2} {z}^{4} \: \times \bigg(\frac{4}{3} \bigg)(1)( - 2) \\ \\ = > \boxed {\red{ \tt\frac{ - 8}{3} {x}^{4} {y}^{2} {z}^{4} }}$