Question

$\frac{4 \sqrt{18} }{ \sqrt{12} } - \frac{8 \sqrt{75} }{ \sqrt{32} } + \frac{9 \sqrt{2} }{ \sqrt{3} }$

Answer 1

4√18/√12-8√75/√32+9√2/√3
4×3√2/2√3 - 40√3 /4√2 +9√2/3
6√2/√3 -10√3/√2 +3√2
12 -30+6√3/√6
18+6√3/√6
6(3+√3)/√6
√6(3+√3)
3√6+√18
3√6+3√2
3(√6+√2)
is your answer

Answer 2

Answer : 0

Hope this helps