Math, asked by rishi555, 1 year ago


 \frac{ 4\sqrt{3} + 5 \sqrt{2}  }{ \sqrt{48}  +  \sqrt{18} }
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Answered by Ankit111a
1

4root3+5root 2/root48+root18

 \frac{4 \sqrt{3} + 5 \sqrt{2}  }{4 \sqrt{3} + 3 \sqrt{2}  }
 \frac{4 \sqrt{3 } + 5 \sqrt{2}  }{4 \sqrt{3} + 3 \sqrt{2}  }  \times  \frac{4 \sqrt{3 } - 3 \sqrt{2}  }{4 \sqrt{3}  - 3 \sqrt{2} }
 \frac{16 \times 3 - 12 \sqrt{6} + 20 \sqrt{6 }  - 30 }{16 \times 3 + 9 \times 2 }
 \frac{68 \sqrt{6} }{66}
Answered by bhoopbhoomi3088
0

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Hello Hope it's helpful for you

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